What is the center ((x+5)^2)/(64)-((y-1)^2)/(36)=1 ?

The center ((x+5)^2)/(64)-((y-1)^2)/(36)=1 is (-5,1)

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center ((x+5)^2)/(64)-((y-1)^2)/(36)=1

center

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

(- 5, 1)

Solution steps

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{64} - \frac{( y - 1 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{8 ^{2}} - \frac{( y - 1 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 1), a = 8, b = 6

And the center is:

(- 5, 1)

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 4 ) ^{2}}{36} = 1

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

x^{2} - (y - 4)^{2} = 1

4 x^{2} - 24 x - 25 y^{2} + 250 y - 489 = 0

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

What is the center ((x+5)^2)/(64)-((y-1)^2)/(36)=1 ?
The center ((x+5)^2)/(64)-((y-1)^2)/(36)=1 is (-5,1)