What is the eccentricity (x^2)/(16)-(y^2)/(64)=1 ?

The eccentricity (x^2)/(16)-(y^2)/(64)=1 is square root of 5

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eccentricity (x^2)/(16)-(y^2)/(64)=1

eccentricity

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

5

Solution steps

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 4, b = 8

= \frac{4 ^{2} + 8 ^{2}}{4}

Refine

= 5

\frac{x ^{2}}{16} - \frac{y ^{2}}{12} = 1

x^{2} - y^{2} < 1

\frac{x ^{2}}{4} - \frac{( y + 1 ) ^{2}}{16} = 1

x^{2} - 4 y^{2} - 2 x + 16 y = 20

5 y^{2} - 16 x^{2} + 400 = 0

What is the eccentricity (x^2)/(16)-(y^2)/(64)=1 ?
The eccentricity (x^2)/(16)-(y^2)/(64)=1 is square root of 5