What is the directrix x-2= 1/8 (y+1)^2 ?

The directrix x-2= 1/8 (y+1)^2 is x=0

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directrix x-2= 1/8 (y+1)^2

directrix

x - 2 = \frac{1}{8} (y + 1)^{2}

x = 0

Solution steps

Rewrite

x - 2 = \frac{1}{8} (y + 1)^{2}

in the standard form:

4 \cdot 2 (x - 2) = (y - (- 1))^{2}

(h, k) = (2, - 1), p = 2

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, - 1)

x-coordinate

x = 2 - p

x = 2 - 2

Refine

x = 0

y = 2 x^{2}

\frac{y ^{2}}{9} - \frac{x ^{2}}{16} = 1

2 x^{2} + 7 y^{2} = 14

49 y^{2} - x^{2} = 49

9 x^{2} + 25 y^{2} = 225