What is x^2+(y-1)^2=1 ?

The solution to x^2+(y-1)^2=1 is Circle with (a,b)=(0,1),r=1

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x^2+(y-1)^2=1

x^{2} + (y - 1)^{2} = 1

(a, b) = (0, 1), r = 1

Solution steps

x^{2} + (y - 1)^{2} = 1

Rewrite

x^{2} + (y - 1)^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 1

x = y^{2} + 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

9 x^{2} - 4 y^{2} - 72 x = 0

f (x) = 2 x^{2} - x - 6

x^{2} - 4 y = 0

What is x^2+(y-1)^2=1 ?
The solution to x^2+(y-1)^2=1 is Circle with (a,b)=(0,1),r=1