What is the vertices (x^2)/(36)-(y^2)/(64)=1 ?

The vertices (x^2)/(36)-(y^2)/(64)=1 is (6,0),(-6,0)

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vertices (x^2)/(36)-(y^2)/(64)=1

vertices

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

(6, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 8

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

9 x^{2} - 16 y^{2} = 144

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1

x^{2} + y^{2} = 7

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{a ^{2}} = 1

What is the vertices (x^2)/(36)-(y^2)/(64)=1 ?
The vertices (x^2)/(36)-(y^2)/(64)=1 is (6,0),(-6,0)