What is the foci (x^2)/9-(y^2)/(25)=1 ?

The foci (x^2)/9-(y^2)/(25)=1 is (sqrt(34),0),(-sqrt(34),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/9-(y^2)/(25)=1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1

(34, 0), (- 34, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{25} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 5^{2} : 34

(0 + 34, 0), (0 - 34, 0)

Refine

(34, 0), (- 34, 0)

y^{2} = - 24 x

y^{2} = x

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

x^{2} = 24 y

3 x^{2} + 3 x + 2 y = 0

What is the foci (x^2)/9-(y^2)/(25)=1 ?
The foci (x^2)/9-(y^2)/(25)=1 is (sqrt(34),0),(-sqrt(34),0)