What is (x^2)/4+(y^2)/(64)=1 ?

The solution to (x^2)/4+(y^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=2,b=8

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(x^2)/4+(y^2)/(64)=1

\frac{x ^{2}}{4} + \frac{y ^{2}}{64} = 1

(h, k) = (0, 0), a = 2, b = 8

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{64} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 2

\frac{( x - 7 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

y^{2} = 1 - x

x^{2} + y^{2} + 4 y - 60 = 0

y^{2} = - 28 x

What is (x^2)/4+(y^2)/(64)=1 ?
The solution to (x^2)/4+(y^2)/(64)=1 is Ellipse with (h,k)=(0,0),a=2,b=8