What is x^2+(y-4)^2=4 ?

The solution to x^2+(y-4)^2=4 is Circle with (a,b)=(0,4),r=2

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x^2+(y-4)^2=4

x^{2} + (y - 4)^{2} = 4

(a, b) = (0, 4), r = 2

Solution steps

x^{2} + (y - 4)^{2} = 4

Rewrite

x^{2} + (y - 4)^{2} = 4

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 2

x^{2} - 6 x + 5 y = - 34

f (x) = x^{2} - 2 x - 3

y + x^{2} = 4 x

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

x^{2} = 8 y

What is x^2+(y-4)^2=4 ?
The solution to x^2+(y-4)^2=4 is Circle with (a,b)=(0,4),r=2