What is the foci (y^2)/9-(x^2)/4 =1 ?

The foci (y^2)/9-(x^2)/4 =1 is (0,sqrt(13)),(0,-sqrt(13))

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foci (y^2)/9-(x^2)/4 =1

foci

\frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1

(0, 13), (0, - 13)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 3, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} + 2^{2} : 13

(0, 0 + 13), (0, 0 - 13)

Refine

(0, 13), (0, - 13)

x^{2} = 3 y

\frac{a + 1}{b} = \frac{a - 1}{b} + \frac{b + 1}{a}

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

y^{2} - y - x + 1 = 0

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

What is the foci (y^2)/9-(x^2)/4 =1 ?
The foci (y^2)/9-(x^2)/4 =1 is (0,sqrt(13)),(0,-sqrt(13))