What is (x^2)/(25)+(y^2)/(16)=1 ?

The solution to (x^2)/(25)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=5,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/(25)+(y^2)/(16)=1

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 5, b = 4

Solution steps

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

x^{2} + (y + 2)^{2} = 4

x = 4 y^{2} + 8 y - 3

\frac{x ^{2}}{16} + y^{2} = 1

y^{2} = - 20 x

What is (x^2)/(25)+(y^2)/(16)=1 ?
The solution to (x^2)/(25)+(y^2)/(16)=1 is Ellipse with (h,k)=(0,0),a=5,b=4