What is the foci (x^2)/(100)+(y^2)/(64)=1 ?

The foci (x^2)/(100)+(y^2)/(64)=1 is (6,0),(-6,0)

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foci (x^2)/(100)+(y^2)/(64)=1

foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 8

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

\frac{x ^{2}}{4} + \frac{y ^{2}}{16} = 1

3 x^{2} + 2 y^{2} = 6

\frac{x ^{2}}{25} + \frac{y ^{2}}{4} = 1

4 x^{2} + y^{2} = 16

y^{2} = - 8 x

What is the foci (x^2)/(100)+(y^2)/(64)=1 ?
The foci (x^2)/(100)+(y^2)/(64)=1 is (6,0),(-6,0)