What is the foci (x-3)^2=-4(y-1) ?

The foci (x-3)^2=-4(y-1) is (3,0)

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foci (x-3)^2=-4(y-1)

foci

(x - 3)^{2} = - 4 (y - 1)

(3, 0)

Solution steps

Rewrite

(x - 3)^{2} = - 4 (y - 1)

in the standard form:

4 (- 1) (y - 1) = (x - 3)^{2}

(h, k) = (3, 1), p = - 1

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, 1)

along the y-axis

(3, 1 + p)

= (3, 1 + (- 1))

Refine

(3, 0)

- (x - 1)^{2}

- x^{2} + 6 x - 9

- x^{2} - 6 x + 15

- 3 x^{2} - 2

(x + 1)^{2} = - 12 (y - 6)