What is 1\div 4+1\div 4 ?

The solution to 1\div 4+1\div 4 is 1/2

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1\div 4+1\div 4

1 \div 4 + 1 \div 4

\frac{1}{2}

Solution steps

1 \div 4 + 1 \div 4

Follow the PEMDAS order of operations

Multiply and divide (left to right)

1 \div 4 : \frac{1}{4}

1 \div 4

1 \div 4 = \frac{1}{4}

= \frac{1}{4}

= \frac{1}{4} + 1 \div 4

Multiply and divide (left to right)

1 \div 4 : \frac{1}{4}

1 \div 4

1 \div 4 = \frac{1}{4}

= \frac{1}{4}

= \frac{1}{4} + \frac{1}{4}

Add and subtract (left to right)

\frac{1}{4} + \frac{1}{4} : \frac{1}{2}

\frac{1}{4} + \frac{1}{4}

\frac{1}{4} + \frac{1}{4} = \frac{1}{2}

\frac{1}{4} + \frac{1}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 1}{4}

Add the numbers:

1 + 1 = 2

= \frac{2}{4}

Cancel the common factor:

2

= \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

1 \div 4 + 1 \div 8

- 3 (- 1)^{2} 1^{3}

(6 + 3)^{4}

3 - 14 \div 7 - 5 \times 4 - 9 \div (- 3) \times (- 4)

(2 \frac{2}{5} - 1) \times \frac{1}{7}