What is -(1)^2+3(1)+2 ?

The solution to -(1)^2+3(1)+2 is 4

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-(1)^2+3(1)+2

- (1)^{2} + 3 (1) + 2

4

Solution steps

- (1)^{2} + 3 (1) + 2

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= - 1 + 3 (1) + 2

Multiply and divide (left to right)

3 (1) : 3

3 (1)

Apply rule:

(a) = a

(1) = 1

= 3 \cdot 1

Multiply the numbers:

3 \cdot 1 = 3

= 3

= - 1 + 3 + 2

Add and subtract (left to right)

- 1 + 3 + 2 : 4

- 1 + 3 + 2

- 1 + 3 = 2

= 2 + 2

2 + 2 = 4

= 4

= 4

6 \div 2 (+ 2)

(- 16) - 6 + (- 5)

1 6^{3} + 5 0^{3} + 3 3^{3}

5 + (3 \times 6 + 5 - 4) + [7 - 5 \times 8]

(3)^{2} + 7