What is (-2)^2+4(-2)-7 ?

The solution to (-2)^2+4(-2)-7 is -11

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(-2)^2+4(-2)-7

(- 2)^{2} + 4 (- 2) - 7

- 11

Solution steps

(- 2)^{2} + 4 (- 2) - 7

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 4 (- 2) - 7

Multiply and divide (left to right)

4 (- 2) : - 8

4 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 2) = - 4 \cdot 2 = - 8

= - 8

= 4 - 8 - 7

Add and subtract (left to right)

4 - 8 - 7 : - 11

4 - 8 - 7

4 - 8 = - 4

= - 4 - 7

- 4 - 7 = - 11

= - 11

= - 11

5 \cdot 5 + 3 \cdot 4^{2} + 10

\frac{2}{5} - \frac{3}{10}

3^{3} + 6 \cdot 3

(2 - \frac{1}{3}) + (3 - \frac{1}{4})

4 (2)^{3} - 8 (2)