What is 3\times (2+3-4)-40\div 20 ?

The solution to 3\times (2+3-4)-40\div 20 is 1

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3\times (2+3-4)-40\div 20

3 \times (2 + 3 - 4) - 40 \div 20

1

Solution steps

3 \times (2 + 3 - 4) - 40 \div 20

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + 3 - 4) : 1

2 + 3 - 4

Add and subtract (left to right)

2 + 3 = 5

= 5 - 4

5 - 4 = 1

= 1

= 3 \times 1 - 40 \div 20

Multiply and divide (left to right)

3 \times 1 : 3

3 \times 1

3 \times 1 = 3

= 3

= 3 - 40 \div 20

Multiply and divide (left to right)

40 \div 20 : 2

40 \div 20

40 \div 20 = 2

= 2

= 3 - 2

Add and subtract (left to right)

3 - 2 : 1

3 - 2

3 - 2 = 1

= 1

= 1

- (2)^{2} + 7

27 + 35 + (- 2) + (- 28)

\frac{1}{3} (- 2)^{2}

(8 - 4) \times 4

3 (3) + 9

What is 3\times (2+3-4)-40\div 20 ?
The solution to 3\times (2+3-4)-40\div 20 is 1