What is 64/3-48+20+4 ?

The solution to 64/3-48+20+4 is -8/3

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64/3-48+20+4

\frac{64}{3} - 48 + 20 + 4

- \frac{8}{3}

Solution steps

\frac{64}{3} - 48 + 20 + 4

Follow the PEMDAS order of operations

Add and subtract (left to right)

\frac{64}{3} - 48 = - \frac{80}{3}

\frac{64}{3} - 48

Convert element to fraction:

48 = \frac{48 \cdot 3}{3}

= - \frac{48 \cdot 3}{3} + \frac{64}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 48 \cdot 3 + 64}{3}

- 48 \cdot 3 + 64 = - 80

- 48 \cdot 3 + 64

Multiply the numbers:

48 \cdot 3 = 144

= - 144 + 64

Add/Subtract the numbers:

- 144 + 64 = - 80

= - 80

= \frac{- 80}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{80}{3}

= - \frac{80}{3} + 20 + 4

- \frac{80}{3} + 20 = - \frac{20}{3}

- \frac{80}{3} + 20

Convert element to fraction:

20 = \frac{20 \cdot 3}{3}

= \frac{20 \cdot 3}{3} - \frac{80}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{20 \cdot 3 - 80}{3}

20 \cdot 3 - 80 = - 20

20 \cdot 3 - 80

Multiply the numbers:

20 \cdot 3 = 60

= 60 - 80

Subtract the numbers:

60 - 80 = - 20

= - 20

= \frac{- 20}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{20}{3}

= - \frac{20}{3} + 4

- \frac{20}{3} + 4 = - \frac{8}{3}

- \frac{20}{3} + 4

Convert element to fraction:

4 = \frac{4 \cdot 3}{3}

= \frac{4 \cdot 3}{3} - \frac{20}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 3 - 20}{3}

4 \cdot 3 - 20 = - 8

4 \cdot 3 - 20

Multiply the numbers:

4 \cdot 3 = 12

= 12 - 20

Subtract the numbers:

12 - 20 = - 8

= - 8

= \frac{- 8}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8}{3}

= - \frac{8}{3}

- 2^{2} - 8 (- 2) + 7

9^{2} - (3 + 6 \div 2) + 8 (15 \times 4 - 60)

2 \cdot 8^{2}

\frac{5}{2} (2)^{0}

3 - (2)^{2}