What is 10-1\times 5^3+9\div 18+3 ?

The solution to 10-1\times 5^3+9\div 18+3 is -223/2

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10-1\times 5^3+9\div 18+3

10 - 1 \times 5^{3} + 9 \div 18 + 3

- \frac{223}{2}

Solution steps

10 - 1 \times 5^{3} + 9 \div 18 + 3

Follow the PEMDAS order of operations

Calculate exponents

5^{3} : 125

5^{3}

5^{3} = 125

= 125

= 10 - 1 \times 125 + 9 \div 18 + 3

Multiply and divide (left to right)

1 \times 125 : 125

1 \times 125

1 \times 125 = 125

= 125

= 10 - 125 + 9 \div 18 + 3

Multiply and divide (left to right)

9 \div 18 : \frac{9}{18}

9 \div 18

9 \div 18 = \frac{9}{18}

= \frac{9}{18}

= 10 - 125 + \frac{9}{18} + 3

Add and subtract (left to right)

10 - 125 + \frac{9}{18} + 3 : - \frac{223}{2}

10 - 125 + \frac{9}{18} + 3

10 - 125 = - 115

= - 115 + \frac{9}{18} + 3

- 115 + \frac{9}{18} = - \frac{229}{2}

= - \frac{229}{2} + 3

- \frac{229}{2} + 3 = - \frac{223}{2}

- \frac{229}{2} + 3

Convert element to fraction:

3 = \frac{3 \cdot 2}{2}

= \frac{3 \cdot 2}{2} - \frac{229}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 2 - 229}{2}

3 \cdot 2 - 229 = - 223

3 \cdot 2 - 229

Multiply the numbers:

3 \cdot 2 = 6

= 6 - 229

Subtract the numbers:

6 - 229 = - 223

= - 223

= \frac{- 223}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{223}{2}

= - \frac{223}{2}

= - \frac{223}{2}

(- 25) \cdot 8 \cdot (- 1)

2 - \frac{5}{2} + \frac{3}{2}

4 (- 4) + 3

3^{2} - 3^{0}

2 (3)^{2} - 4 (3) - 6

What is 10-1\times 5^3+9\div 18+3 ?
The solution to 10-1\times 5^3+9\div 18+3 is -223/2