What is 3(12-31/4)-31/4 ?

The solution to 3(12-31/4)-31/4 is 5

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3(12-31/4)-31/4

3 (12 - \frac{31}{4}) - \frac{31}{4}

5

Solution steps

3 (12 - \frac{31}{4}) - \frac{31}{4}

Follow the PEMDAS order of operations

Calculate within parentheses

(12 - \frac{31}{4}) : \frac{17}{4}

12 - \frac{31}{4}

12 - \frac{31}{4} = \frac{17}{4}

12 - \frac{31}{4}

Convert element to fraction:

12 = \frac{12 \cdot 4}{4}

= \frac{12 \cdot 4}{4} - \frac{31}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{12 \cdot 4 - 31}{4}

12 \cdot 4 - 31 = 17

12 \cdot 4 - 31

Multiply the numbers:

12 \cdot 4 = 48

= 48 - 31

Subtract the numbers:

48 - 31 = 17

= 17

= \frac{17}{4}

= \frac{17}{4}

= 3 \cdot \frac{17}{4} - \frac{31}{4}

Multiply and divide (left to right)

3 \cdot \frac{17}{4} : \frac{51}{4}

3 \cdot \frac{17}{4}

Convert element to fraction:

3 = \frac{3}{1}

= \frac{3}{1} \cdot \frac{17}{4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 17}{1 \cdot 4}

Multiply the numbers:

3 \cdot 17 = 51

= \frac{51}{1 \cdot 4}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{51}{4}

= \frac{51}{4} - \frac{31}{4}

Add and subtract (left to right)

\frac{51}{4} - \frac{31}{4} : 5

\frac{51}{4} - \frac{31}{4}

\frac{51}{4} - \frac{31}{4} = 5

\frac{51}{4} - \frac{31}{4}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{51 - 31}{4}

Subtract the numbers:

51 - 31 = 20

= \frac{20}{4}

Divide the numbers:

\frac{20}{4} = 5

= 5

= 5

= 5

1 0^{2} + (- 4)^{3}

(2 - 10) \cdot (6 - 3) - (- 8 - 2) \cdot (- 9 - 7)

15 \div \frac{3}{4} + 4

- 3 \times 3^{2}

6 \div 2 (3 \times 1)