What is (-3)^2+(4)^2+(5-7)^2 ?

The solution to (-3)^2+(4)^2+(5-7)^2 is 29

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(-3)^2+(4)^2+(5-7)^2

(- 3)^{2} + (4)^{2} + (5 - 7)^{2}

29

Solution steps

(- 3)^{2} + (4)^{2} + (5 - 7)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 7) : - 2

5 - 7

5 - 7 = - 2

= - 2

= (- 3)^{2} + (4)^{2} + (- 2)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 + (4)^{2} + (- 2)^{2}

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 9 + 16 + (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 9 + 16 + 4

Add and subtract (left to right)

9 + 16 + 4 : 29

9 + 16 + 4

9 + 16 = 25

= 25 + 4

25 + 4 = 29

= 29

= 29

((6192 - 96) + 16) + 8 + 4

7 + 5 \div \frac{1}{2} - 17 \div (3 + \frac{8}{3})

- 2 (1)^{2} + 4

- 2 (1)^{2} - 2

(2 \times 7 - 4^{2}) - 10