The solution to -(1-2)^2+6 is 5

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-(1-2)^2+6

Solution

- (1 - 2)^{2} + 6

5

Solution steps

- (1 - 2)^{2} + 6

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - 2) : - 1

1 - 2

1 - 2 = - 1

= - 1

= - (- 1)^{2} + 6

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 + 6

Add and subtract (left to right)

- 1 + 6 : 5

- 1 + 6

- 1 + 6 = 5

= 5

= 5

3 (4)^{2} - 3

(3 \frac{5}{7} - \frac{2}{7}) \div 4

2 - 2 \times 1

3 + 8^{2} \div 4 \times 5 - 2

5 (- 16 \div 21 - 13) - 3 (- 7 + 15)