What is 8\div (10\div 5)-4\div (2)\times (2) ?

The solution to 8\div (10\div 5)-4\div (2)\times (2) is 0

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8\div (10\div 5)-4\div (2)\times (2)

8 \div (10 \div 5) - 4 \div (2) \times (2)

0

Solution steps

8 \div (10 \div 5) - 4 \div (2) \times (2)

Follow the PEMDAS order of operations

Calculate within parentheses

(10 \div 5) : 2

10 \div 5

10 \div 5 = 2

= 2

= 8 \div 2 - 4 \div (2) \times (2)

Multiply and divide (left to right)

8 \div 2 : 4

8 \div 2

8 \div 2 = 4

= 4

= 4 - 4 \div (2) \times (2)

Multiply and divide (left to right)

4 \div (2) \times (2) : 4

4 \div (2) \times (2)

4 \div (2) = \frac{4}{( 2 )}

= \frac{4}{( 2 )} \times (2)

\frac{4}{( 2 )} \times (2) = 4

\frac{4}{2} (2)

Apply rule:

(a) = a

(2) = 2

= \frac{4}{2} \cdot 2

Convert element to fraction:

2 = \frac{2}{1}

= \frac{4}{2} \cdot \frac{2}{1}

Cross-cancel common factor:

2

= \frac{4}{1}

Divide the numbers:

\frac{4}{1} = 4

= 4

= 4

= 4 - 4

Add and subtract (left to right)

4 - 4 : 0

4 - 4

4 - 4 = 0

= 0

= 0

(25 + 1) (25 - 1)

14 - \frac{9}{3} + 2

- 4 (- 2) + 1

{20 + [12 + (7 - 3) + 5] - 10} - 20

7 (- 2)^{2}

What is 8\div (10\div 5)-4\div (2)\times (2) ?
The solution to 8\div (10\div 5)-4\div (2)\times (2) is 0