What is 4+(-1\times (-2-1)^2) ?

The solution to 4+(-1\times (-2-1)^2) is -5

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4+(-1\times (-2-1)^2)

4 + (- 1 \cdot (- 2 - 1)^{2})

- 5

Solution steps

4 + (- 1 \cdot (- 2 - 1)^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(- 1 \cdot (- 2 - 1)^{2}) : - 9

- 1 \cdot (- 2 - 1)^{2}

Calculate within parentheses

(- 2 - 1) : - 3

- 2 - 1

- 2 - 1 = - 3

= - 3

= - 1 \cdot (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 1 \cdot 9

Multiply and divide (left to right)

- 1 \cdot 9 : - 9

- 1 \cdot 9

- 1 \cdot 9 = - 9

= - 9

= - 9

= 4 - 9

Add and subtract (left to right)

4 - 9 : - 5

4 - 9

4 - 9 = - 5

= - 5

= - 5

- 8 - 8 + 7

\frac{7}{5} - (\frac{3}{10} + \frac{1}{3})

(- 2) + (- 3) + (+ 8)

- 8 - 7 + 7

- 3^{2} + 2 \cdot (- 3) + 7