What is 48\div (2^2-29)+6^2 ?

The solution to 48\div (2^2-29)+6^2 is 34 2/25

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Popular >

48\div (2^2-29)+6^2

Solution

48 \div (2^{2} - 29) + 6^{2}

Solution

34 \frac{2}{25}

Solution steps

48 \div (2^{2} - 29) + 6^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(2^{2} - 29) : - 25

2^{2} - 29

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 - 29

Add and subtract (left to right)

4 - 29 : - 25

4 - 29

4 - 29 = - 25

= - 25

= - 25

= 48 \div (- 25) + 6^{2}

Calculate exponents

6^{2} : 36

6^{2}

6^{2} = 36

= 36

= 48 \div (- 25) + 36

Multiply and divide (left to right)

48 \div (- 25) : \frac{48}{( - 25 )}

48 \div (- 25)

Apply rule

a \div (- b) = - a \div b

48 \div (- 25) = - 48 \div 25 = \frac{48}{( - 25 )}

= \frac{48}{( - 25 )}

= \frac{48}{( - 25 )} + 36

Add and subtract (left to right)

\frac{48}{( - 25 )} + 36 : \frac{852}{25}

\frac{48}{( - 25 )} + 36

\frac{48}{( - 25 )} + 36 = \frac{852}{25}

\frac{48}{- 25} + 36

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{48}{25} + 36

Convert element to fraction:

36 = \frac{36 \cdot 25}{25}

= \frac{36 \cdot 25}{25} - \frac{48}{25}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{36 \cdot 25 - 48}{25}

36 \cdot 25 - 48 = 852

36 \cdot 25 - 48

Multiply the numbers:

36 \cdot 25 = 900

= 900 - 48

Subtract the numbers:

900 - 48 = 852

= 852

= \frac{852}{25}

= \frac{852}{25}

= \frac{852}{25}

Convert improper fractions to mixed numbers:

\frac{852}{25} = 34 \frac{2}{25}

\frac{852}{25} = 34

Remainder

2

\frac{852}{25}

Write the problem in long division format

25 \overline{∣ 852}

Divide

85

25

to get

3

Divide

85

25

to get

3

3 25 \overline{∣ 852}

Multiply the quotient digit

(3)

by the divisor

25

3 25 \overline{∣ 852} \underline{75}

Subtract

75

from

85

3 25 \overline{∣ 852} \underline{75} 10

Bring down the next number of the dividend

3 25 \overline{∣ 852} \underline{75} 102

3 25 \overline{∣ 852} \underline{75} 102

Divide

102

25

to get

4

Divide

102

25

to get

4

34 25 \overline{∣ 852} \underline{75} 102

Multiply the quotient digit

(4)

by the divisor

25

34 25 \overline{∣ 852} \underline{75} 102 \underline{100}

Subtract

100

from

102

34 25 \overline{∣ 852} \underline{75} 102 \underline{100} 2

34 25 \overline{∣ 852} \underline{75} 102 \underline{100} 2

The solution for Long Division of

\frac{852}{25}

34

with remainder of

2

34 Remainder 2

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{852}{25} = 34 \frac{2}{25}

= 34 \frac{2}{25}

= 34 \frac{2}{25}

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Frequently Asked Questions (FAQ)

What is 48\div (2^2-29)+6^2 ?
The solution to 48\div (2^2-29)+6^2 is 34 2/25