What is 2(-3)^1+5^1 ?

The solution to 2(-3)^1+5^1 is -1

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2(-3)^1+5^1

2 (- 3)^{1} + 5^{1}

- 1

Solution steps

2 (- 3)^{1} + 5^{1}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{1} : - 3

(- 3)^{1}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3)^{1} = - 3^{1} = - 3

= - 3

= 2 (- 3) + 5^{1}

Calculate exponents

5^{1} : 5

5^{1}

5^{1} = 5

= 5

= 2 (- 3) + 5

Multiply and divide (left to right)

2 (- 3) : - 6

2 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 3) = - 2 \cdot 3 = - 6

= - 6

= - 6 + 5

Add and subtract (left to right)

- 6 + 5 : - 1

- 6 + 5

- 6 + 5 = - 1

= - 1

= - 1

- 77 + [- 56 - 65 - 54 + (- 8)]

21 - [- (3 - 4) - 3] - 5

- (4 - 4)^{2} - 4

310 \div 5 \times 16 + 240 \div 6 \times 5

(- 5)^{2} + 6 (- 5) + 8