What is (2\div 3)-1 ?

The solution to (2\div 3)-1 is -1/3

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(2\div 3)-1

(2 \div 3) - 1

- \frac{1}{3}

Solution steps

(2 \div 3) - 1

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \div 3) : \frac{2}{3}

2 \div 3

2 \div 3 = \frac{2}{3}

= \frac{2}{3}

= \frac{2}{3} - 1

Add and subtract (left to right)

\frac{2}{3} - 1 : - \frac{1}{3}

\frac{2}{3} - 1

\frac{2}{3} - 1 = - \frac{1}{3}

\frac{2}{3} - 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= - \frac{1 \cdot 3}{3} + \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 3 + 2}{3}

- 1 \cdot 3 + 2 = - 1

- 1 \cdot 3 + 2

Multiply the numbers:

1 \cdot 3 = 3

= - 3 + 2

Add/Subtract the numbers:

- 3 + 2 = - 1

= - 1

= \frac{- 1}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{3}

= - \frac{1}{3}

= - \frac{1}{3}

24 \div 2 - 8 - 2 (- 3)^{2} - 2

1 \div 2 + 1 \div 3 + 1 \div 6

2 (- 3) - 2

3^{2} (3 \cdot 3^{4})

3 (4)^{2} - 6 (5 - 10)