What is -(2)^2+4(2)-1 ?

The solution to -(2)^2+4(2)-1 is 3

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-(2)^2+4(2)-1

- (2)^{2} + 4 (2) - 1

3

Solution steps

- (2)^{2} + 4 (2) - 1

Follow the PEMDAS order of operations

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= - 4 + 4 (2) - 1

Multiply and divide (left to right)

4 (2) : 8

4 (2)

Apply rule:

(a) = a

(2) = 2

= 4 \cdot 2

Multiply the numbers:

4 \cdot 2 = 8

= 8

= - 4 + 8 - 1

Add and subtract (left to right)

- 4 + 8 - 1 : 3

- 4 + 8 - 1

- 4 + 8 = 4

= 4 - 1

4 - 1 = 3

= 3

= 3

- (2)^{2} + 4 (2) - 3

- (2)^{2} + 4 (2) + 5

2 (- 2)^{2} - 5 (- 2) - 3

2 \times 1 6^{2}

5^{2} \div 17