What is 9(4-10)+28\div 7+5^2 ?

The solution to 9(4-10)+28\div 7+5^2 is -25

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9(4-10)+28\div 7+5^2

9 (4 - 10) + 28 \div 7 + 5^{2}

- 25

Solution steps

9 (4 - 10) + 28 \div 7 + 5^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 10) : - 6

4 - 10

4 - 10 = - 6

= - 6

= 9 (- 6) + 28 \div 7 + 5^{2}

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 9 (- 6) + 28 \div 7 + 25

Multiply and divide (left to right)

9 (- 6) : - 54

9 (- 6)

Apply rule

a \cdot (- b) = - a \cdot b

9 (- 6) = - 9 \cdot 6 = - 54

= - 54

= - 54 + 28 \div 7 + 25

Multiply and divide (left to right)

28 \div 7 : 4

28 \div 7

28 \div 7 = 4

= 4

= - 54 + 4 + 25

Add and subtract (left to right)

- 54 + 4 + 25 : - 25

- 54 + 4 + 25

- 54 + 4 = - 50

= - 50 + 25

- 50 + 25 = - 25

= - 25

= - 25

(2 \times (- 7))^{2}

(139 \times 12) + (263 - 15)

4^{2} - 6 (4) + 10

\frac{20}{3} \cdot (- 4) + \frac{100}{3}

10 (30) - 20