What is 2\times (-3)^2-(-3)+2 ?

The solution to 2\times (-3)^2-(-3)+2 is 23

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2\times (-3)^2-(-3)+2

2 \cdot (- 3)^{2} - (- 3) + 2

23

Solution steps

2 (- 3)^{2} - (- 3) + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 2 \cdot 9 - (- 3) + 2

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= 18 - (- 3) + 2

Add and subtract (left to right)

18 - (- 3) + 2 : 23

18 - (- 3) + 2

Apply rule

- (- a) = + a

- (- 3) = + 3

= 18 + 3 + 2

18 + 3 = 21

= 21 + 2

21 + 2 = 23

= 23

= 23

11 - 4 + 13 - 2 - 6 + 3

180 - 25 - 90

82 + (- 100) + (- 1) + 76

20 - 4^{2}

2^{3} + 2^{2} + 2^{1} + 2^{0}