What is (-1)^2+(-1)^3-(-1)^4+1^3 ?

The solution to (-1)^2+(-1)^3-(-1)^4+1^3 is 0

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(-1)^2+(-1)^3-(-1)^4+1^3

(- 1)^{2} + (- 1)^{3} - (- 1)^{4} + 1^{3}

0

Solution steps

(- 1)^{2} + (- 1)^{3} - (- 1)^{4} + 1^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 + (- 1)^{3} - (- 1)^{4} + 1^{3}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= 1 - 1 - (- 1)^{4} + 1^{3}

Calculate exponents

(- 1)^{4} : 1

(- 1)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{4} = 1^{4} = 1

= 1

= 1 - 1 - (- 1)^{4} + 1^{3}

Calculate exponents

1^{3} : 1

1^{3}

1^{3} = 1

= 1

= 1 - 1 - (- 1)^{4} + 1^{3}

Add and subtract (left to right)

1 - 1 - (- 1)^{4} + 1^{3} : 0

1 - 1 - (- 1)^{4} + 1^{3}

1 - 1 = 0

= 0 - (- 1)^{4} + 1^{3}

0 - (- 1)^{4} = - 1

= - 1 + 1^{3}

- 1 + 1^{3} = 0

= 0

= 0

2 - 29 - (- 8) - 11

2^{22} + 2^{10} + 1

(2 \frac{1}{2} + 3 \frac{1}{4}) - 1 \frac{1}{4}

[6 \times 3 + (3 \times 1)] - 10

- 6 - (- 9) \div 3

What is (-1)^2+(-1)^3-(-1)^4+1^3 ?
The solution to (-1)^2+(-1)^3-(-1)^4+1^3 is 0