What is (-1)^2+5(-1)+6 ?

The solution to (-1)^2+5(-1)+6 is 2

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(-1)^2+5(-1)+6

(- 1)^{2} + 5 (- 1) + 6

2

Solution steps

(- 1)^{2} + 5 (- 1) + 6

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 + 5 (- 1) + 6

Multiply and divide (left to right)

5 (- 1) : - 5

5 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 1) = - 5 \cdot 1 = - 5

= - 5

= 1 - 5 + 6

Add and subtract (left to right)

1 - 5 + 6 : 2

1 - 5 + 6

1 - 5 = - 4

= - 4 + 6

- 4 + 6 = 2

= 2

= 2

2 (7 - 4) + 3 (7 - 5) + 8

7 (2 - 3 (4 + (- 2) \times 5))

202 3^{2} - 202 2^{2}

15 \div 30 \times 100

\frac{( 59 + 2 ^{2} )}{3 ^{2}}