What is 14-25+(32\div (-2))(-5)+6(-1-3)^2 ?

The solution to 14-25+(32\div (-2))(-5)+6(-1-3)^2 is 165

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14-25+(32\div (-2))(-5)+6(-1-3)^2

14 - 25 + (32 \div (- 2)) (- 5) + 6 (- 1 - 3)^{2}

165

Solution steps

14 - 25 + (32 \div (- 2)) (- 5) + 6 (- 1 - 3)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(32 \div (- 2)) : - 16

32 \div (- 2)

Apply rule

a \div (- b) = - a \div b

32 \div (- 2) = - 32 \div 2 = - 16

= - 16

= 14 - 25 - 16 (- 5) + 6 (- 1 - 3)^{2}

Calculate within parentheses

(- 1 - 3) : - 4

- 1 - 3

- 1 - 3 = - 4

= - 4

= 14 - 25 - 16 (- 5) + 6 (- 1 - 3)^{2}

Calculate exponents

(- 1 - 3)^{2} : 16

(- 1 - 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1 - 3)^{2} = (1 - 3)^{2} = 16

= 16

= 14 - 25 - 16 (- 5) + 6 \cdot 16

Multiply and divide (left to right)

16 (- 5) : - 80

16 (- 5)

Apply rule

a \cdot (- b) = - a \cdot b

16 (- 5) = - 16 \cdot 5 = - 80

= - 80

= 14 - 25 - (- 80) + 6 \cdot 16

Multiply and divide (left to right)

6 \cdot 16 : 96

6 \cdot 16

6 \cdot 16 = 96

= 96

= 14 - 25 - (- 80) + 96

Add and subtract (left to right)

14 - 25 - (- 80) + 96 : 165

14 - 25 - (- 80) + 96

14 - 25 = - 11

= - 11 - (- 80) + 96

Apply rule

- (- a) = + a

- (- 80) = + 80

= - 11 + 80 + 96

- 11 + 80 = 69

= 69 + 96

69 + 96 = 165

= 165

= 165

5 - 3 [7 + 6 (- 9 + 7)]

(32 + 10) \times 5

- (- 4) - 4 (- 4) - 3

0 \times 4 - 1 \times 4

(3^{3} \div 9) + 2

What is 14-25+(32\div (-2))(-5)+6(-1-3)^2 ?
The solution to 14-25+(32\div (-2))(-5)+6(-1-3)^2 is 165