What is (-2)^3\times 4^2-10 ?

The solution to (-2)^3\times 4^2-10 is -138

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(-2)^3\times 4^2-10

(- 2)^{3} \cdot 4^{2} - 10

- 138

Solution steps

(- 2)^{3} \cdot 4^{2} - 10

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 \cdot 4^{2} - 10

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= - 8 \cdot 16 - 10

Multiply and divide (left to right)

- 8 \cdot 16 : - 128

- 8 \cdot 16

- 8 \cdot 16 = - 128

= - 128

= - 128 - 10

Add and subtract (left to right)

- 128 - 10 : - 138

- 128 - 10

- 128 - 10 = - 138

= - 138

= - 138

- 3 + (3 \times 7 + 12) + 4 - 12

3^{2} \div (- 3)^{2}

- 3 \times (- 2) (3 \times (- 4))

12 \times 10 + 30 \div (6 - 3) \times 4 + 1

- 2^{2} + 6 (- 2) + 9