What is (-2)^3+4(-2)+7 ?

The solution to (-2)^3+4(-2)+7 is -9

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(-2)^3+4(-2)+7

(- 2)^{3} + 4 (- 2) + 7

- 9

Solution steps

(- 2)^{3} + 4 (- 2) + 7

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 + 4 (- 2) + 7

Multiply and divide (left to right)

4 (- 2) : - 8

4 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 2) = - 4 \cdot 2 = - 8

= - 8

= - 8 - 8 + 7

Add and subtract (left to right)

- 8 - 8 + 7 : - 9

- 8 - 8 + 7

- 8 - 8 = - 16

= - 16 + 7

- 16 + 7 = - 9

= - 9

= - 9

4 - (- 1) + (- 2)

74 \div 14 - 3 [10 - 2 (8 - 3)]

(- 8) + (- 6) - (- 7)

9^{2} - 5 8^{0}

15 + 3 \times 7 - 2 \times 3 + 8 \div 2