What is (3)^2-2(3)+7 ?

The solution to (3)^2-2(3)+7 is 10

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(3)^2-2(3)+7

(3)^{2} - 2 (3) + 7

10

Solution steps

(3)^{2} - 2 (3) + 7

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 9 - 2 (3) + 7

Multiply and divide (left to right)

2 (3) : 6

2 (3)

Apply rule:

(a) = a

(3) = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= 9 - 6 + 7

Add and subtract (left to right)

9 - 6 + 7 : 10

9 - 6 + 7

9 - 6 = 3

= 3 + 7

3 + 7 = 10

= 10

= 10

(2)^{2} (\frac{1}{2}) (\frac{1}{3})

(+ 12) - (5 + 8)

(10 - 3)^{2} + 2 \cdot [6 - 5 (3^{2} - 2)^{2}]

- 13 + 6 + (- 8) + 13

- 2 \times 0 + 2