What is -1-3/7 (-3)^2 ?

The solution to -1-3/7 (-3)^2 is -34/7

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-1-3/7 (-3)^2

- 1 - \frac{3}{7} (- 3)^{2}

- \frac{34}{7}

Solution steps

- 1 - \frac{3}{7} (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 1 - \frac{3}{7} \cdot 9

Multiply and divide (left to right)

\frac{3}{7} \cdot 9 : \frac{27}{7}

\frac{3}{7} \cdot 9

Convert element to fraction:

9 = \frac{9}{1}

= \frac{3}{7} \cdot \frac{9}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 9}{7 \cdot 1}

Multiply the numbers:

3 \cdot 9 = 27

= \frac{27}{7 \cdot 1}

Multiply the numbers:

7 \cdot 1 = 7

= \frac{27}{7}

= - 1 - \frac{27}{7}

Add and subtract (left to right)

- 1 - \frac{27}{7} : - \frac{34}{7}

- 1 - \frac{27}{7}

- 1 - \frac{27}{7} = - \frac{34}{7}

= - \frac{34}{7}

= - \frac{34}{7}

+ 8 - 30 - 50

5 (1500) + 3

- 9 + 4 + (- 14) + 9

(5 - 8)^{2}

4 (2)^{6}