What is (-1)^{12}+(-1)^{25}-(-1)^{19}-(+1)^{32} ?

The solution to (-1)^{12}+(-1)^{25}-(-1)^{19}-(+1)^{32} is 0

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(-1)^{12}+(-1)^{25}-(-1)^{19}-(+1)^{32}

(- 1)^{12} + (- 1)^{25} - (- 1)^{19} - (+ 1)^{32}

0

Solution steps

(- 1)^{12} + (- 1)^{25} - (- 1)^{19} - (1)^{32}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{12} : 1

(- 1)^{12}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{12} = 1^{12} = 1

= 1

= 1 + (- 1)^{25} - (- 1)^{19} - (1)^{32}

Calculate exponents

(- 1)^{25} : - 1

(- 1)^{25}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{25} = - 1^{25} = - 1

= - 1

= 1 - 1 - (- 1)^{19} - (1)^{32}

Calculate exponents

(- 1)^{19} : - 1

(- 1)^{19}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{19} = - 1^{19} = - 1

= - 1

= 1 - 1 - (- 1)^{19} - (1)^{32}

Calculate exponents

(1)^{32} : 1

(1)^{32}

(1)^{32} = 1

= 1

= 1 - 1 - (- 1)^{19} - (1)^{32}

Add and subtract (left to right)

1 - 1 - (- 1)^{19} - (1)^{32} : 0

1 - 1 - (- 1)^{19} - (1)^{32}

1 - 1 = 0

= 0 - (- 1)^{19} - (1)^{32}

0 - (- 1)^{19} = 1

= 1 - (1)^{32}

1 - (1)^{32} = 0

= 0

= 0

(- 5 - 5)^{2}

(6 \div 19) - (5 \div 7)

2 5^{2} \div 7^{2}

14 (- 8)^{2} + 6

(- 27) + 20 - 8

What is (-1)^{12}+(-1)^{25}-(-1)^{19}-(+1)^{32} ?
The solution to (-1)^{12}+(-1)^{25}-(-1)^{19}-(+1)^{32} is 0