What is -3(-3)^2+2(-3)+2 ?

The solution to -3(-3)^2+2(-3)+2 is -31

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-3(-3)^2+2(-3)+2

- 3 (- 3)^{2} + 2 (- 3) + 2

- 31

Solution steps

- 3 (- 3)^{2} + 2 (- 3) + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= - 3 \cdot 9 + 2 (- 3) + 2

Multiply and divide (left to right)

- 3 \cdot 9 : - 27

- 3 \cdot 9

- 3 \cdot 9 = - 27

= - 27

= - 27 + 2 (- 3) + 2

Multiply and divide (left to right)

2 (- 3) : - 6

2 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 3) = - 2 \cdot 3 = - 6

= - 6

= - 27 - 6 + 2

Add and subtract (left to right)

- 27 - 6 + 2 : - 31

- 27 - 6 + 2

- 27 - 6 = - 33

= - 33 + 2

- 33 + 2 = - 31

= - 31

= - 31

2 (5 + 4)

\frac{1}{( 1 0 ^{3} 7 )}

\frac{1 - 2}{( 1 ) ^{2} - 4}

20 - 3 \times 6 + 8

7 - 2 \cdot 5 + 7 \cdot 3 - 2 \cdot 4 - 3 \cdot 4