What is (4)^2-8(4)+13 ?

The solution to (4)^2-8(4)+13 is -3

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(4)^2-8(4)+13

(4)^{2} - 8 (4) + 13

- 3

Solution steps

(4)^{2} - 8 (4) + 13

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 16 - 8 (4) + 13

Multiply and divide (left to right)

8 (4) : 32

8 (4)

Apply rule:

(a) = a

(4) = 4

= 8 \cdot 4

Multiply the numbers:

8 \cdot 4 = 32

= 32

= 16 - 32 + 13

Add and subtract (left to right)

16 - 32 + 13 : - 3

16 - 32 + 13

16 - 32 = - 16

= - 16 + 13

- 16 + 13 = - 3

= - 3

= - 3

3 (4)^{2} - 8 (4) - 3

(13 + 28 \div 7) [6 (48 \div 2) - (20 \div 4 + 9)]

16 \div 8 + 6 \times 3 - 2

20 - (- 12) - (- 3)

2^{3} + 2^{2} + 4