What is 5(3^2)+4^2+3(3)+4(4) ?

The solution to 5(3^2)+4^2+3(3)+4(4) is 86

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5(3^2)+4^2+3(3)+4(4)

5 (3^{2}) + 4^{2} + 3 (3) + 4 (4)

86

Solution steps

5 (3^{2}) + 4^{2} + 3 (3) + 4 (4)

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{2}) : 9

3^{2}

3^{2} = 9

= 9

= 5 \cdot 9 + 4^{2} + 3 (3) + 4 (4)

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 5 \cdot 9 + 16 + 3 (3) + 4 (4)

Multiply and divide (left to right)

5 \cdot 9 : 45

5 \cdot 9

5 \cdot 9 = 45

= 45

= 45 + 16 + 3 (3) + 4 (4)

Multiply and divide (left to right)

3 (3) : 9

3 (3)

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= 45 + 16 + 9 + 4 (4)

Multiply and divide (left to right)

4 (4) : 16

4 (4)

Apply rule:

(a) = a

(4) = 4

= 4 \cdot 4

Multiply the numbers:

4 \cdot 4 = 16

= 16

= 45 + 16 + 9 + 16

Add and subtract (left to right)

45 + 16 + 9 + 16 : 86

45 + 16 + 9 + 16

45 + 16 = 61

= 61 + 9 + 16

61 + 9 = 70

= 70 + 16

70 + 16 = 86

= 86

= 86

\frac{1}{1 + 2 ^{2}}

\frac{1}{2} \cdot 1 2^{2}

(4 + \frac{1}{2} + \frac{1}{4}) \div 4

5 \times 1 0^{0}

5^{6} - 4^{6}