What is -1/3 (-3)^3 ?

The solution to -1/3 (-3)^3 is 9

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-1/3 (-3)^3

- \frac{1}{3} (- 3)^{3}

9

Solution steps

- \frac{1}{3} (- 3)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{3} : - 27

(- 3)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3)^{3} = - 3^{3} = - 27

= - 27

= - \frac{1}{3} (- 27)

Multiply and divide (left to right)

- \frac{1}{3} (- 27) : 9

- \frac{1}{3} (- 27)

Apply rule

- a \cdot (- b) = a \cdot b

- \frac{1}{3} (- 27) = \frac{1}{3} \cdot 27

Convert element to fraction:

27 = \frac{27}{1}

= \frac{1}{3} \cdot \frac{27}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 27}{3 \cdot 1}

\frac{1 \cdot 27}{3 \cdot 1} = 9

\frac{1 \cdot 27}{3 \cdot 1}

\frac{1 \cdot 27}{3 \cdot 1} = \frac{27}{3}

\frac{1 \cdot 27}{3 \cdot 1}

Multiply the numbers:

1 \cdot 27 = 27

= \frac{27}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{27}{3}

= \frac{27}{3}

Divide the numbers:

\frac{27}{3} = 9

= 9

= 9

= 9

1 + 2 (2)^{2}

\frac{36 \div 3 \times ( 8 - 6 )}{6}

- (1) + (4 - 4)

8^{3} + 8^{3} + 8^{3} + 8^{3}

1^{2} - 45