What is 4-2{3[5-2(5-6)-7]+10}+17 ?

The solution to 4-2{3[5-2(5-6)-7]+10}+17 is 1

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4-2{3[5-2(5-6)-7]+10}+17

4 - 2 {3 [5 - 2 (5 - 6) - 7] + 10} + 17

1

Solution steps

4 - 2 {3 [5 - 2 (5 - 6) - 7] + 10} + 17

Follow the PEMDAS order of operations

Calculate within parentheses

{3 [5 - 2 (5 - 6) - 7] + 10} : 10

3 [5 - 2 (5 - 6) - 7] + 10

Calculate within parentheses

[5 - 2 (5 - 6) - 7] : 0

5 - 2 (5 - 6) - 7

Calculate within parentheses

(5 - 6) : - 1

5 - 6

5 - 6 = - 1

= - 1

= 5 - 2 (- 1) - 7

Multiply and divide (left to right)

2 (- 1) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= 5 - (- 2) - 7

Add and subtract (left to right)

5 - (- 2) - 7 : 0

5 - (- 2) - 7

Apply rule

- (- a) = + a

- (- 2) = + 2

= 5 + 2 - 7

5 + 2 = 7

= 7 - 7

7 - 7 = 0

= 0

= 0

= 3 \cdot 0 + 10

Multiply and divide (left to right)

3 \cdot 0 : 0

3 \cdot 0

3 \cdot 0 = 0

= 0

= 0 + 10

Add and subtract (left to right)

0 + 10 : 10

0 + 10

0 + 10 = 10

= 10

= 10

= 4 - 2 \cdot 10 + 17

Multiply and divide (left to right)

2 \cdot 10 : 20

2 \cdot 10

2 \cdot 10 = 20

= 20

= 4 - 20 + 17

Add and subtract (left to right)

4 - 20 + 17 : 1

4 - 20 + 17

4 - 20 = - 16

= - 16 + 17

- 16 + 17 = 1

= 1

= 1

(+ 35)^{0} + (- 6) \div (- 6) + 2^{3}

- 2^{3} - 6 (- 2)

- 4 (1) + 1

- 4 (1) - 3

- 100 + 40 - 65 - 35 + 160

What is 4-2{3[5-2(5-6)-7]+10}+17 ?
The solution to 4-2{3[5-2(5-6)-7]+10}+17 is 1