What is (-2)^3+(-4)^2-2\times 3^2-3^2 ?

The solution to (-2)^3+(-4)^2-2\times 3^2-3^2 is -19

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-2)^3+(-4)^2-2\times 3^2-3^2

(- 2)^{3} + (- 4)^{2} - 2 \cdot 3^{2} - 3^{2}

- 19

Solution steps

(- 2)^{3} + (- 4)^{2} - 2 \cdot 3^{2} - 3^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 + (- 4)^{2} - 2 \cdot 3^{2} - 3^{2}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 8 + 16 - 2 \cdot 3^{2} - 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 8 + 16 - 2 \cdot 9 - 3^{2}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 8 + 16 - 2 \cdot 9 - 9

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= - 8 + 16 - 18 - 9

Add and subtract (left to right)

- 8 + 16 - 18 - 9 : - 19

- 8 + 16 - 18 - 9

- 8 + 16 = 8

= 8 - 18 - 9

8 - 18 = - 10

= - 10 - 9

- 10 - 9 = - 19

= - 19

= - 19

(92 - 61) + (- 8 \times 4) - 20 \div 4

- (4)^{2} + 12 (4) - 32

24 \div 3 \div 2 \times 5

(2)^{2} - (2) - 2

3 (- 2)^{2} - 2

What is (-2)^3+(-4)^2-2\times 3^2-3^2 ?
The solution to (-2)^3+(-4)^2-2\times 3^2-3^2 is -19