What is (2/4+3/2)^2 ?

The solution to (2/4+3/2)^2 is 4

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(2/4+3/2)^2

(\frac{2}{4} + \frac{3}{2})^{2}

4

Solution steps

(\frac{2}{4} + \frac{3}{2})^{2}

\frac{2}{4} = \frac{1}{2}

Cancel the common factor:

2

\frac{1}{2}

= (\frac{1}{2} + \frac{3}{2})^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{1}{2} + \frac{3}{2}) : 2

\frac{1}{2} + \frac{3}{2}

\frac{1}{2} + \frac{3}{2} = 2

\frac{1}{2} + \frac{3}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 3}{2}

Add the numbers:

1 + 3 = 4

= \frac{4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2

= 2

= 2^{2}

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4

1 + 2^{2} + 3^{2}

7 + 7 \times 7

\frac{1}{2} (23 - 5)

(0)^{2} - 4 (0) + 4

+ 6 - (7 - 8 + 9) + (3 - 4) + 2 - 3