What is 4(6)^2-32(6)+48 ?

The solution to 4(6)^2-32(6)+48 is 0

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4(6)^2-32(6)+48

4 (6)^{2} - 32 (6) + 48

0

Solution steps

4 (6)^{2} - 32 (6) + 48

Follow the PEMDAS order of operations

Calculate exponents

(6)^{2} : 36

(6)^{2}

(6)^{2} = 36

= 36

= 4 \cdot 36 - 32 (6) + 48

Multiply and divide (left to right)

4 \cdot 36 : 144

4 \cdot 36

4 \cdot 36 = 144

= 144

= 144 - 32 (6) + 48

Multiply and divide (left to right)

32 (6) : 192

32 (6)

Apply rule:

(a) = a

(6) = 6

= 32 \cdot 6

Multiply the numbers:

32 \cdot 6 = 192

= 192

= 144 - 192 + 48

Add and subtract (left to right)

144 - 192 + 48 : 0

144 - 192 + 48

144 - 192 = - 48

= - 48 + 48

- 48 + 48 = 0

= 0

= 0

17 \times 1 + 1

(3)^{4} - 2 (3)^{3}

- 5 \cdot 2 2^{2} + 110 \cdot 22

(4 - 4)^{2} + 3

10 \cdot 5^{3}