What is (-8)\div [(-12)-(+12)+(-8)] ?

The solution to (-8)\div [(-12)-(+12)+(-8)] is 1/4

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(-8)\div [(-12)-(+12)+(-8)]

(- 8) \div [(- 12) - (+ 12) + (- 8)]

\frac{1}{4}

Solution steps

(- 8) \div [(- 12) - (12) + (- 8)]

Follow the PEMDAS order of operations

Calculate within parentheses

[(- 12) - (12) + (- 8)] : - 32

(- 12) - (12) + (- 8)

Add and subtract (left to right)

(- 12) - (12) = - 24

= - 24 + (- 8)

Apply rule

+ (- a) = - a

+ (- 8) = - 8

= - 24 - 8

- 24 - 8 = - 32

= - 32

= (- 8) \div (- 32)

Multiply and divide (left to right)

(- 8) \div (- 32) : \frac{( - 8 )}{( - 32 )}

(- 8) \div (- 32)

Apply rule

(- a) \div (- b) = a \div b

(- 8) \div (- 32) = 8 \div 32 = \frac{( - 8 )}{( - 32 )}

= \frac{( - 8 )}{( - 32 )}

= \frac{( - 8 )}{( - 32 )}

Simplify

\frac{( - 8 )}{( - 32 )} : \frac{1}{4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{8}{32}

Cancel the common factor:

8

= \frac{1}{4}

\frac{1}{50} (5)^{3}

26 \cdot 2 \div 4 - (6 + 4)^{2} + 3 (5 - 2)^{3}

2 + 1 \div 2 + 1

(2 (1) - 4)^{50}

2 (2)^{3} - 4

What is (-8)\div [(-12)-(+12)+(-8)] ?
The solution to (-8)\div [(-12)-(+12)+(-8)] is 1/4