What is -200(1-5/50) ?

The solution to -200(1-5/50) is -180

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-200(1-5/50)

- 200 (1 - \frac{5}{50})

- 180

Solution steps

- 200 (1 - \frac{5}{50})

\frac{5}{50} = \frac{1}{10}

Cancel the common factor:

5

\frac{1}{10}

= - 200 (1 - \frac{1}{10})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{1}{10}) : \frac{9}{10}

1 - \frac{1}{10}

1 - \frac{1}{10} = \frac{9}{10}

1 - \frac{1}{10}

Convert element to fraction:

1 = \frac{1 \cdot 10}{10}

= \frac{1 \cdot 10}{10} - \frac{1}{10}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 10 - 1}{10}

1 \cdot 10 - 1 = 9

1 \cdot 10 - 1

Multiply the numbers:

1 \cdot 10 = 10

= 10 - 1

Subtract the numbers:

10 - 1 = 9

= 9

= \frac{9}{10}

= \frac{9}{10}

= - 200 \cdot \frac{9}{10}

Multiply and divide (left to right)

- 200 \cdot \frac{9}{10} : - 180

- 200 \cdot \frac{9}{10}

Convert element to fraction:

200 = \frac{200}{1}

= - \frac{200}{1} \cdot \frac{9}{10}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{200}{1} \cdot \frac{9}{10} = \frac{200 \cdot 9}{1 \cdot 10}

= - \frac{200 \cdot 9}{1 \cdot 10}

Cancel

\frac{200 \cdot 9}{1 \cdot 10} : 180

\frac{200 \cdot 9}{1 \cdot 10}

Multiply the numbers:

1 \cdot 10 = 10

= \frac{200 \cdot 9}{10}

Divide the numbers:

\frac{200}{10} = 20

= 20 \cdot 9

Multiply the numbers:

20 \cdot 9 = 180

= 180

= - 180

= - 180

3 0^{2} + 7 2^{2}

5 (- 6) \div (7 - 10)

(15 + 5 \times 4) \div 7

(4) + (5) (2) + (40) \div (10) - 7

- 3 (8 - 30)