What is (4-2)^3-(3)2+4 ?

The solution to (4-2)^3-(3)2+4 is 6

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(4-2)^3-(3)2+4

(4 - 2)^{3} - (3) 2 + 4

6

Solution steps

(4 - 2)^{3} - (3) \cdot 2 + 4

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - 2) : 2

4 - 2

4 - 2 = 2

= 2

= 2^{3} - (3) \cdot 2 + 4

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 - (3) \cdot 2 + 4

Multiply and divide (left to right)

(3) \cdot 2 : 6

(3) \cdot 2

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

= 8 - 6 + 4

Add and subtract (left to right)

8 - 6 + 4 : 6

8 - 6 + 4

8 - 6 = 2

= 2 + 4

2 + 4 = 6

= 6

= 6

(- 6)^{4} \cdot (- 2) \div 5^{3}

4 + (6 (- 2)) + 15 (- 1)

35 \times 5 + 40 - 15 \times 2

(- 10) + (- 10) + (- 10) + (- 10) + (- 10) + (- 10)

- 1^{2} - 2 \times 2^{2} + 4 \times 1^{2}