The solution to 7/4-(-1)^2 is 3/4

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7/4-(-1)^2

Solution

\frac{7}{4} - (- 1)^{2}

\frac{3}{4}

Solution steps

\frac{7}{4} - (- 1)^{2}

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= \frac{7}{4} - 1

Add and subtract (left to right)

\frac{7}{4} - 1 : \frac{3}{4}

\frac{7}{4} - 1

\frac{7}{4} - 1 = \frac{3}{4}

\frac{7}{4} - 1

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= - \frac{1 \cdot 4}{4} + \frac{7}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 4 + 7}{4}

- 1 \cdot 4 + 7 = 3

- 1 \cdot 4 + 7

Multiply the numbers:

1 \cdot 4 = 4

= - 4 + 7

Add/Subtract the numbers:

- 4 + 7 = 3

= 3

= \frac{3}{4}

= \frac{3}{4}

= \frac{3}{4}

(2 - 1)^{2} - 3

7^{2} \cdot 5

2 7^{2} - 125

\frac{15 ( 2 + 30 )}{2}

- 4 + (- 12) + (- 3)