What is 5(3)^2(2)^3-4(3)(2)^2+3(3)-9 ?

The solution to 5(3)^2(2)^3-4(3)(2)^2+3(3)-9 is 312

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5(3)^2(2)^3-4(3)(2)^2+3(3)-9

5 (3)^{2} (2)^{3} - 4 (3) (2)^{2} + 3 (3) - 9

312

Solution steps

5 (3)^{2} (2)^{3} - 4 (3) (2)^{2} + 3 (3) - 9

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 5 \cdot 9 (2)^{3} - 4 (3) (2)^{2} + 3 (3) - 9

Calculate exponents

(2)^{3} : 8

(2)^{3}

(2)^{3} = 8

= 8

= 5 \cdot 9 \cdot 8 - 4 (3) (2)^{2} + 3 (3) - 9

Calculate exponents

(2)^{2} : 4

(2)^{2}

(2)^{2} = 4

= 4

= 5 \cdot 9 \cdot 8 - 4 (3) \cdot 4 + 3 (3) - 9

Multiply and divide (left to right)

5 \cdot 9 \cdot 8 : 360

5 \cdot 9 \cdot 8

5 \cdot 9 = 45

= 45 \cdot 8

45 \cdot 8 = 360

= 360

= 360 - 4 (3) \cdot 4 + 3 (3) - 9

Multiply and divide (left to right)

4 (3) \cdot 4 : 48

4 (3) \cdot 4

4 (3) = 12

4 (3)

Apply rule:

(a) = a

(3) = 3

= 4 \cdot 3

Multiply the numbers:

4 \cdot 3 = 12

= 12

= 12 \cdot 4

12 \cdot 4 = 48

= 48

= 360 - 48 + 3 (3) - 9

Multiply and divide (left to right)

3 (3) : 9

3 (3)

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= 360 - 48 + 9 - 9

Add and subtract (left to right)

360 - 48 + 9 - 9 : 312

360 - 48 + 9 - 9

360 - 48 = 312

= 312 + 9 - 9

312 + 9 = 321

= 321 - 9

321 - 9 = 312

= 312

= 312

\frac{1}{2} \times 4^{2}

5 \times [- 6 + (- 3 - 10 + 5) + 6] - (- 10 - 3)

- 9 + 8 - 5

2 (- 2)^{2} - 8 (- 2)

(19 - 4)^{3}

What is 5(3)^2(2)^3-4(3)(2)^2+3(3)-9 ?
The solution to 5(3)^2(2)^3-4(3)(2)^2+3(3)-9 is 312